Christian sold tickets to the game. good seats were $5 each and poor seats cost $2 each. 210 people attended and paid $660. write a system of linear equations that can be used to find how many good seats (g) and how many poor seats (p) were sold.

Let g represent the # of good seats and p the # of poor ones.

Then g + p = 210 seats.  Then p = 210 - g.

Revenue:  ($5)g + ($2)p = $660.  Substituting 210 - g for p, 

                   ($5)g + ($2)(210 - g) = $660

Simplifying, 5g + 420 - 2g = 660 => 3g = 240  =>  g = 80

Then there were 80 good seats and (210-80), or 130, poor seats.

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