When looking at a rational function f of x equals the quantity x minus six times the quantity x plus three times the quantity x plus four all divided by the quantity x plus six times the quantity x minus three times the quantity x minus four , jamal and angie have two different thoughts. jamal says that the function is defined at x = −6, x = 3, and x = 4. angie says that the function is undefined at those x values. who is correct? justify your reasoning. (10 points)

1) The rational function f(x) is:
         
            (x - 6) (x + 3) (x + 4)
f(x) =
            (x + 6) (x - 3) (x - 4)

2) As you must know the division by 0 is not defined, so the function f(x) is not defined when the denominator is 0.

3) The denominator is 0 when any of the factors in it is 0.

4) x + 6 = 0 => x = - 6 => the function f(x) is not defined at x = - 6

5) x - 3 = 0 => x = 3 => fhe function f(x) is not defined at x = 3

6) x - 4 = 0 =. x = 4 => the function f(x) is not defined at x = 4

So, it has bee proven that Angie is correct.

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