(06.02 mc) the equation of line ef is y = 2x + 1. write an equation of a line parallel to line ef in slope-intercept form that contains point (0, 2). (5 points) y = 2x − 4 y = 2x + 2 y = negative 1 over 2 x − 4 y = negative 1 over 2 x + 2

The line equation that we want to find is:

y = 2*x + 2

A general linear equation is:

y = a*x + b

Where a is the slope and b is the y-intercept.

We know that two lines are parallel if the lines have the same slope but different y-intercept.

So if we want our line to be parallel to EF, we must have something like:

y = 2*x + c

To find the value of c, we use the fact that our line contains the point (0, 2), then we have:

2 = 2*0 + c

2 = c

So the line is:

y = 2*x + 2.

If you want to learn more about linear equations, you can read:

link

check above link.

graphically?   well, you graph them both, the solutions is where they both intersect each other, since there are two solutions, meaning they will meet twice, or namely the linear will run into the quadratic curve twice, and where they meet, those x,y coordinates are the solutions to the system.