High temperatures in a certain city for the month of august follow a uniform distribution over the interval 63 degrees upper f63°f to 93 degrees f.93°f. what is the probability that a randomly selected august day has a high temperature that exceeded 68 degrees f question mark

The notation for the uniform distribution is X ~ U(a, b), where a = the lowest value and b = the highest value In your case, X ~ U(66,89) µ = (b+a)/2 Ď = (b-a)²/12 In this case, a = 66 and b = 89 Thus, µ = (89+66)/2 = 77.5 Ď = (89-66)²/12 = 44.0833 Then, because we now know the true/population µ and Ď, we can use z-scores. z = (X-µ)/Ď In our case, X = 71. So, Z = (X-µ)/Ď Z = (71-77.5)/44.0833 = -0.15 P(Z>-0.15) = P(Z<0.15) = 0.5596