Write a equation of a line that is perpendicular to the given line and that passes through the given points. y-2=7/3(x+5); (-4,9)a. y-9=-3/7(x-4) b. y-9=3/7(x+4) c. y-9=-3/7(x+4) d. y-9= 3/7(x-4)

6: 07 is your answer

step-by-step explanation:

the equation of the parallel line would be y = 2x + 9

step-by-step explanation:

to start we need to find the slope of the original line. we can do that by looking at the coefficient of x, which is 2

since the slope of the original line is 2 and parallel lines have the same slope, we know the new line will also have 2 slope. now we can use that along with the point given in point-slope form to get the find equation.

y - y1 = m(x - x1)

y - 5 = 2(x + 2)

y - 5 = 2x + 4

y = 2x + 9