Do you think it's possible to create a function with any given set of x- intercepts?

An x-intercept is where y is zero. With the law of mutiplying by zero, we know that: If a * b = 0, then a, b, or both must be zero. So if we want that a function will be zero at 4 and 2, we need to find a function which equals zero at these points. x = 2 / subtract 2 from both sides. x - 2 = 0 So the expression is (x - 2). The expression for x = 4 is (x - 4). Now we just multiply them and give the function a name: y = (x - 2)(x - 4) y = x^2 - 6x + 8. 2. Same idea: y = (x + 6)(x - 3) y = x^2 +3x - 18. 3. Once again, same idea: y = (x + 5)(x - 5)(x - 1) Since (x + 5)(x - 5) = x^2 - 25, we can calculate: y = (x^2 -25)(x - 1) y = x^3 - x^2 -25x + 25. 4. As explained above, yes. 5. Yes, there is an infinite number of functions that fit the conditions of those questions. Just multiply the same factor over and over: For 1: y = (x - 2)(x - 2)(x - 4) y = (x^2 - 6x + 8)(x - 2) y = x^3 - 8x^2 + 20x - 16. The same goes for 2 and 3.

In all honesty, there really is no “work” per say to show. mainly it’s just using the process of elimination. the question is asking which domain(s) would be the most appropriate for the function c(n). n is the number of observed vehicles so right away, 1, 2, and 3 can be eliminated.why? 1, 2 start in the negatives and therefore it is impossible to observe negative cars. so, #4 would be the best answer to the given problem.