Abox contains 3 red chips and 2 green chips. chips are drawn randomly, one at a time without replacement, until all 3 of the reds are drawn or until both green chips are drawn. what is the probability that the 3 reds are drawn

The total number of chips is 5; 

Without replacement, on the first try, there is 3/5 probability of getting a red chip. 
The second chip's probability would be 2/4 and the third being 1/3 

(3/5)(2/4)(1/3)=6/20 

Therefore, the probability of drawing 3 reds first is 6/20.

Hope I helped :) 

Abit confused about what you mean, but i think you might be referring to slope intercept form: y = mx + bin that case b, or the y intercept is already given.(0,-1)find the slope by using the formulay2 - y1/x2 - x1the final slope will be 4/2, equivalent to 2.now your equation should look like thisy = 4/2x -1sorry if this didn’t you out!