Which graph represents the solution set for the system 6x + y > -3 and 2x + y ≤ 4? a. graph a b. graph b c. graph c d. graph d

Option B. Graph B

Step-by-step explanation:

The given system of the inequalities are 6x + y > -3 and 2x + y ≤ 4

If we take the first inequality which represents the area below the line 6x + y = -3 or y = -6x - 3 (Slope of the line -6 and y-intercept is -3)

Second graph is represented by 2x + y ≤ 4 which represents the area below  the line y = 4 - 2x ( slope = -2 and y intercept = 4)

Option B shows the shaded area which the common area representing the solution set of these systems.

the answer would be 150 books

step-by-step explanation:

if you divide 300 by 2 you will get 150

answer: (c) m∠qpo + (2x + 16)° = 180°

step-by-step explanation:

the opposite angles of a quadrilateral are supplementary.

so, ∠o + ∠q = 180°   and   ∠p + ∠r = 180°

since ∠r = 2x + 16°, we can use substitution as follows:

∠p + ∠r = 180°

∠p + (2x + 16)° = 180°