Mathematics
Mathematics, 21.07.2019 23:50, bryce99

Simplify: negative two and one-third minus negative ten and one-sixth a negative twelve and one-half b twelve and one-half c seven and five-sixths d negative seven and five-sixths determine the answer to (βˆ’3) + (βˆ’5) and explain the steps using a number line. give example and how you did it use absolute value to express the distance between βˆ’12 and βˆ’15 on the number line. a |βˆ’12 βˆ’ (βˆ’15)| = βˆ’27 b |βˆ’12 βˆ’ (βˆ’15)| = βˆ’3 c |βˆ’12 βˆ’ (βˆ’15)| = 3 d |βˆ’12 βˆ’ (βˆ’15)| = 27 im failing and its stressing

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Simplify: negative two and one-third minus negative ten and one-sixth a negative twelve and one-ha...

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