Select the system of linear inequalities whose solution is graphed. coordinate plane with a system of two linear inequalities. the first is a solid line graphed with a slope of negative one, y-intercept of negative 2, and the region containing the origin is shaded. the second is a dashed vertical line 3 units to the left of the origin, and the region containing the origin is shaded. x ≥ –3; y ≥ x – 2 x > –3; 5y ≥ –4x – 10 x > –3; y ≥ –x + 1 x > –2; y ≥ –x – 1

Step-by-step explanation:

The first line has "equal to" because it is solid. It follows the same form as

where m is the slope which is -1 and b is the y-intercept which is -2.

This means the equation is .

The second line is 3 units to the left of the origin and is dashed so is or . Since it is 3 units and is including the origin (numbers greater than) then the line is

given that triangle abc is transformed two times to get triangle

a"b"c"

first abc is transformed in to a'b'c' as follows:

the coordinates of a are (1,-1) and transformed into a'(-1,1)

similarly b (4,-2) became b'(-4,2) and

c(7,-2) became c'(-7,2)

i.e. (x,y) becomes (-x,-y)

this is nothing but reflection about a point here origin.

thus first transformation is reflection on the origin.

next is exactly shifting 3 units down

source:

-232

step-by-step explanation: