The great foods warehouse contains 9435 pounds of watermelons. there are 6555.569 pounds of watermelons in the tasty food warehouse. how many more pounds does the tasty food warehouse need to have the same amount of watermelons as the great food warehouse?

2879.431 pounds

Step-by-step explanation:

Given : The Great Foods Warehouse contains 9435 pounds of watermelons.

There are 6555.569 pounds of watermelons in the Tasty Food Warehouse.

Clearly , 9435 > 6555.569.

By using Subtraction operation, The amount of watermelon needed by Tasty Food Warehouse to have to get the same amount of watermelons as the Great Food Warehouse will be :-

9435-6555.569=2879.431 pounds

Hence, the Tasty Food Warehouse needs to have 2879.431 pounds to gwt the same amount of watermelons as the Great Food Warehouse.

an

y = 6x -3y -12

y +3y +12 = 6x

=> . x = { 2y / 3 +2 } this is equation of line in terms of x

=> . if line meets the x-axis the co-ordinates of meeting point would be ( x , 0 )

=> . x = 2 ( 0 ) / 3 + 2

=> . x = 2

so, the point is ( 2 , 0 )