Acompany manufactures and sells x meras per month the monthly revnuee function is given by r(x)=200x-0.02x+1000 a) what is the maximum monthly revenue? b) how many cameras should be produced to maximize the monthl revenue?

Hnmmmn not sure

Ibelieve the answer is c i worked it out three times but if my answer is wrong someone correct me

One shot. if 60% of 10 is 6, then what is 70%? we know it would be seven (since 60% is mathematically 60/100, or 6/10, then 70% is 70/100, or 7/10) but we can check anyway using ratios: 6 : 60% = x : 70%*inverse multiplicationx * 60% = 6 * 70%*divide both sides by 60%x = (6 * 70%) / 60%x = 7and since he has made 6 shots already, he would need just one more to get 7 shots or 70%. if the explanation is too confusing, comment and i will try to