The sum of four consecutive integers is 166. find the largest of the numbers if the smallest is z.

4 consecutive integers...z, z + 1, z + 2, z + 3

z + (z + 1) + (z + 2) + (z + 3) = 166...combine like terms
4z + 6 = 166
4z = 166 - 6
4z = 160
z = 160/4
z = 40

z + 1 = 40 + 1 = 41
z + 2 = 40 + 2 = 42
z + 3 = 40 + 3 = 43

so ur numbers are : 40,41,42,43 with the largest being 43

2/1 or just 2. sorry if i get this wrong