Mathematics, 21.07.2019 12:10, u8p4

Consider points a(3, 6) and b(8, 4). find point c on the x-axis so ac +bc is a minimum.

Answers: 1

Show answers

Answers

Both points are below the x-axis. You can solve this by thinking of the x-axis as a mirror, I suppose?

Anyway, you have to pick point C:(x,0) on the x-axis. Draw AC and BC.

Now you have to reflect B:(12,-5) in the x-axis, to B':(12,5), and draw B'C; its the reflection in the x-axis of BC.

Finding the shortest line in the original problem is connecting A and B', calling its point of intersection with the x-axis, C.

Then AC+BC will be minimized.

Find x, and thus, C:
A: (4,-3)
B: (12,5)
C: (x, 0)

(0+3)/(x-4) = (5+3)/(12-4) = 1
3 = x - 4
x = 7

C: (7,0)

Well, that took a while. And it sure does look confusing. Hope you'll be able to read it properly.
Consider points a(3, 6) and b(8, 4). find point c on the x-axis so ac +bc is a minimum.

Consider points a(3, 6) and b(8, 4). find point c on the x-axis so ac +bc is a minimum.

answered: Guest

answer: on graphs, the open and closed circles, or vertical asymptotes drawn as dashed lines us identify discontinuities.

as before, graphs and tables allow us to estimate at best.

when working with formulas, getting zero in the denominator indicates a point of discontinuity.

when working with piecewise-defined functions, check for discontinuities at the transition points where one piece ends and the next begins.

step-by-step explanation:

answered: Guest

1. sometimes

2. never

3 .08c = 7.50+.05c 250 pages

step-by-step explanation:

1. sometimes

the theoretical probability of rolling a 1 is 1/6. perhaps you got really lucky and never rolled a 1 in those 60 times. your experimental probability is 0. or perhaps you rolled a 1 20 times. your experimental probability is 20/60 is 1/3. it really just depends on how you rolled in that experiment.

2. never

the probability of the event occurring is 1. that is being 100 % sure it will happen. that is the maximum amount of confidence we have.

3. no customer card cost: .08 times number of pages

customer card cost: 7.50 + .05 times number of pages

we want to find when it costs the same amount, so we will set these equal

let c = number of pages

.08c = 7.50+.05c

subtract .05c from each side

.08c-.05c = 7.5+.05c-.05c

.03c=7.5

divide each side by .03

.03c/.03 = 7.5/03