Anut mixture of almonds and cashew nuts at a small fair is $1.00 per pound of almonds and $3.55 per pound of cashew nuts. over the entire day, 65 pounds of the nut mixture were sold for $189.95. if p is the number almonds and n is the number of cashew nuts, then the system of equations that models this scenario is: p+n=65p+3.55n=189.95p+n=65p+3.55n=1 89.95 determine the correct description and amount of pounds for almonds and cashew nuts that were sold. a (26.0, 39.0)there were 26.0 pounds of almonds and 39.0 pounds of cashew nuts sold at the fair. b (16.0, 49.0)there were 16.0 pounds of almonds and 49.0 pounds of cashew nuts sold at the fair. c (49.0, 16.0)there were 49.0 pounds of almonds and 16.0 pounds of cashew nuts sold at the fair. d (39.0, 26.0)there were 39.0 pounds of almonds and 26.0 pounds of cashew nuts sold at the fair.

B. (16.0, 49.0) There were 16.0 pounds of almonds and 49.0 pounds of cashew nuts sold at the fair.

Step-by-step explanation:

Here, p represents the number of pounds of almond and n be the number of pounds of cashew nuts,

Since, total nuts = 65

⇒ p + n = 65 (1)

Also, the total spending is $ 189.95 in which almond costs $ 1.00 per pounds and cashew costs $ 3.55 per pound,

⇒ p + 3.55n = 189.95 (2)

Equation (1) - equation (2),

2.55n = 124.95

⇒ n = 49

From equation (1),

p + 49 = 65 ⇒ p = 16

Hence, there are 16 pounds of almonds and 49 pounds of cashew.

7! = 7×6×5×4×3×2

3! = 3× 2

as 7! is multiple of 3! because 7! contains 3! that is 3× 2 as factor

so 7! /(3! ) = 7× 6× 5× 4

= 42 × 20

= 840

its b) 840✌✌✌

dhruv⭐

the length of o'p' is .

step-by-step explanation:

it is given that the quadrilateral m'n'o'p' is the image of quadrilateral mnop after dilation.

the center of dilation is origin and the scale factor is 1.5.

in dilation the image and preimge are similar figures. it means the sides of image and preimage are proportional.

the scale factor is defined as

the scale factor is 1.5.

multiply both sides by op.

note: if the value of op is given, then multiply the value of op with 1.5 to get the length of side o'p'.

therefore length of o'p' is .