In triangle abc shown below, side ab is 8 and side ac is 6: triangle abc with segment joining point d on segment ab and point e on segment ac. which statement is needed to prove that segment de is half the length of segment bc? segment ad is 3, and segment ae is 4. segment ad is 3, and segment ae is 6. segment ad is 4, and segment ae is 6. segment ad is 4, and segment ae is 3.

Segment AD is 4, and segment AE is 3.

Step-by-step explanation:

Given,

In triangle ABC,

AB = 8 unit,

AC = 6 unit,

We have to prove :

[tex]DE=\frac{BC}{2}{/tex]

By the Midpoint Theorem, the segment joining two sides of a triangle at the midpoints of those sides is parallel to the third side and is half the length of the third side.

Thus, for proving the required statement we need to prove D and E are midpoints of AB and AC respectively,

That is, AD = DB and AE = EC

∵ AB = 8 ⇒ AD + DB = 8 ⇒ AD + AD = 8 ⇒ 2AD = 8 ⇒ AD = 4

Similarly,

2AE = 6 ⇒ AE = 3

Hence, LAST option is correct.

answer: domain and range mean all possible values of x and y that could be substituted to the inequality. a solution means all possible values that make the inequality statement true. so while the range is still all real numbers, the solution is the shaded area, for which y will always be greater than the line of the function.

he has now walked a total of what?

if i know what this is maybe i can

step-by-step explanation: