Determine where the real zeros of f(x)= 2x^4 + x^2 - 3x + 3 are located a. between -1 & 0 c. between 1 & 2 b. between 0 & 1 d. no real zeros

Step-by-step explanation:

I used calculus to find the answer.  Newton's Method is used to determine where real zeros exist in a polynomial.  Couldn't factor it to find them, so I went with Newton's Method.  My iterations began at a zero of .475 then jumped to 2.070168876, then to 1.545902463, then to 1.135355003, then to .7521218306, then to -.2695537736. then to .783503098.  It was the last iteration there that told me there were no real zeros.  When the answers jump from positive to negative and back to positive, the Method fails and there are no real zeros.  So d.

$4

step-by-step explanation:

$30×5=$150

$150 minus $130=$20

$20÷5=$4.

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