The french club is sponsoring a bake sale. if their goal is to raise at least $135, how many pastries must they sell at $3.00 each in order to meet that goal? write and solve an inequality. 135p ≥ 3.00; p ≥ 45 3.00p ≥ 135; p ≥ 405 3.00p ≥ 135; p ≥ 45 3.00p ≥ 135; p ≥ 132

3.00p ≹ 135; p ≹ 45 let's create our own equation and then see what option best matches. the french club is selling pastries, so we'll use the variable p. each pastry sells for $3.00, so we can write 3p as the amount of money they'll raise by selling pastries. so 3p now they want to raise at least $135. so let's set the equation we have to be greater than or equal to 135. giving 3p ≹ 135 solving for p, we get p ≹ 45 now let's look at the available options and see what matches: 135p ≹ 3.00; p ≹ 45 * got the correct answer, but the inequality is all wrong. so bad choice. 3.00p ≹ 135; p ≹ 405 * the inequality looks good (2 extra decimal points doesn't matter). but the answer is wrong. so still a bad choice. 3.00p ≹ 135; p ≹ 45 * both the inequality and answer looks good. this is the right choice. 3.00p ≹ 135; p ≹ 132 * good inequality, don't know where the answer came from. so bad choice.

In all honesty, there really is no “work” per say to show. mainly it’s just using the process of elimination. the question is asking which domain(s) would be the most appropriate for the function c(n). n is the number of observed vehicles so right away, 1, 2, and 3 can be eliminated.why? 1, 2 start in the negatives and therefore it is impossible to observe negative cars. so, #4 would be the best answer to the given problem.