find the perimeter of a quadrilateral with vertices at c (−1, 2), d (−2, −1), e (2, −2), and f (1, 1). round your answer to the nearest hundredth when necessary. 10.92 units 12.68 units 13.43 units 18.27 units

Refer to the graph shown below.the distance between two points (x₁,  y₁) and (x₂, y₂) istherefored₁ = cd =  √[(-1)²+(-3)²] = 3.1623d₂ = de =  √[(4)²+(-1)²] = 4.1231d₃ = ef =  √[(1)²+(-3)²] =  3.1623d₄ = cf =  √[(2)²+(-1)²] = 2.2361the perimeter isd₁+d₂+d₃+d₄ = 3.1623+4.1231+3.1623+2.2361 = 12.6837answer: 12.68 units (nearest hundredth)

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