Which steps could be part of the process in algebraically solving the system of equations, y + 5x = x2 + 10 and y = 4x – 10? check all that apply. y = x2 + 5x + 10 y + 5x = x2 + 10 + 4x – 10 4x – 10 = x2 – 5x + 10 0 = x2 – 9x 0 = x2 – 9x + 20 one x-value of a solution to the system is 4.

IT'S meep  4x – 10 = x2 – 5x + 10  ( y = 4x - 10 is substitute for y)

 PROOF:        y + 5x = x² + 10
                      (4x - 10) + 5x = x² + 10
                       4x - 10  =  x² -5x + 10
     
    
0 = x2 – 9x + 20  (liked terms are grouped and simplified)

PROOF:      4x - 10  =  x² -5x + 10
                    4x = x² -5x + 10 + 10
                     0  = x² -5x -4x + 20
                     0  = x² - 9x + 20

Solving:
              x² - 9x + 20 = 0 

              x² - 5x - 4x + 20 = 0

              (x - 5) (x - 4)  = 0

           ⇒ x = 4  (as question says) OR x = 5

1. isolate the variable, in this case, d. subtract 35.5 on both sides of the equation.2. 52 subtracted by 35.5 is 16.53. therefore your answer would be d= 16.5this is the basics of pre algebra, isolating variable through adding, subtracting, multiplying, and dividing, if you have any other questions to ask just comment!