Determine the discriminant for the quadratic equation -3 = x^2 + 4^x + 1. based on the discriminant value, how many real number solutions does the equation have? discriminant = b^2 - 4ac

Answer with Step-by-step explanation:

We are given a quadratic equation:

which could also be written as:

The discriminant of the equation ax²+bx+c=0 is d=b²-4ac

Here a=1,b=4,c=4

d=4²-4×1×4=0

Hence, discriminant is zero

⇒ There is 1 real solution

(Since, when discriminant is positive i.e. d>0 then we have 2 real solutions

when discriminant is negative i.e. d<0 then we have 0 real solutions

and when discriminant is zero i.e. d=0 then we have 1 real solution)

the equivalent expression are always the hardest ones but you look at the gcf also

step-by-step explanation: