Find the work done by the force field f(x, y,z)=2xi+2yj+4k on a particle that moves along the helix r(t)=2cos(t)i+2sin(t)j+5tk,0≤t≤2π.

because 1.2 isnt half of 6 duh

area of part 1:

a1=base*height/2=(8+2)*(8-2-2-1)/2=10*3/2=15 ft^2

area of part 2:

a2=length*width=(8+2)*1=10 ft2

area of part 3:

a3=length*width=8*2=16 ft2

total shaded area : a1+a2+a3=41 ft2

total area of the reactangle : a=16*8=128 ft2

total area of the nonshaded region : 128-41=87 ft2