The waiting times between a subway departure schedule and the arrival of a passenger are uniformly distributed between 00 and 66 minutes. find the probability that a randomly selected passenger has a waiting time greater than greater than 2.252.25 minutes.

You refer to a rectangular distribution. 

I.e. Area ∝ probability 

so, length x height = area 

=> 6 x height = 1 

so, height = 1/6 

Therefore, greater than 2.25 minutes => 8-2.25 = 5.75 minutes 

=> 5.75 x 1/6 = 0.9583

Since this is uniformly distributed, there is no need to find the height or standard deviation.

i think this could be a possible answer (1 / 84) -1

good luck! : d

answer: 7270

step-by-step explanation: