Accomplished silver workers in india can pound silver into incredibly thin sheets, as thin as 3.00 10-7 m (about one-hundredth of the thickness of a sheet of paper). find the area of such a sheet that can be formed from 2.90 kg of silver.

The density of silver is 10,500 kg/m^3, therefore the volume of a 2.90 kg silver is:

V = 2.90 kg / (10,500 kg/m^3)

V = 0.000276 m^3

We know that volume is simply area times height:

Volume = Area * height

SO the area is:

Area = 0.000276 m^3 / 3.00 x 10-7 m

Area = 920.63 m^2

-2

7 - 9 = -2

reversed:

-2 + 9 = 7

i’m here for points.