Which shows the following expression using positive exponents? m^7n^3/mn^-1, m=0, and n=0

Hello There!

It would be option A, based on my work.

My apologies if it's incorrect.

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- Hannah ❤

Ok it should not have a negative3 (m-2)-5=8-2 (m-4) Simplifying 3(m + -2) + -5 = 8 + -2(m + -4) Reorder the terms: 3(-2 + m) + -5 = 8 + -2(m + -4) (-2 * 3 + m * 3) + -5 = 8 + -2(m + -4) (-6 + 3m) + -5 = 8 + -2(m + -4) Reorder the terms: -6 + -5 + 3m = 8 + -2(m + -4) Combine like terms: -6 + -5 = -11 -11 + 3m = 8 + -2(m + -4) Reorder the terms: -11 + 3m = 8 + -2(-4 + m) -11 + 3m = 8 + (-4 * -2 + m * -2) -11 + 3m = 8 + (8 + -2m) Combine like terms: 8 + 8 = 16 -11 + 3m = 16 + -2m Solving -11 + 3m = 16 + -2m Solving for variable 'm'. Move all terms containing m to the left, all other terms to the right. Add '2m' to each side of the equation. -11 + 3m + 2m = 16 + -2m + 2m Combine like terms: 3m + 2m = 5m -11 + 5m = 16 + -2m + 2m Combine like terms: -2m + 2m = 0 -11 + 5m = 16 + 0 -11 + 5m = 16 Add '11' to each side of the equation. -11 + 11 + 5m = 16 + 11 Combine like terms: -11 + 11 = 0 0 + 5m = 16 + 11 5m = 16 + 11 Combine like terms: 16 + 11 = 27 5m = 27 Divide each side by '5'. m = 5.4 Simplifying there fore my answer is A lol sorry 

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