The base of a triangle is seven less than twice its height. if the area of the triangle is 100cm^2 find the length of the base explain this too me i'm stuck

h≈4.874 cm,b≈21.748 cm

Atriangle=12bh

"The base of a triangle is twelve more than twice its height."

From this we can say that:

b=2h+12

So, if A=12bh, we can replace b with 2h+12.

A=12(2h+12)h

53=12(2h+12)h

53=(h+6)h

53=h2+6h

h2+6h−53=0

Use the quadratic formula.

h=−6±√62−4(−53)(1)2

h≈4.874

(Ignore the negative answer—height can't be negative.)

b≈2(4.874)+12

b≈21.748

answer rather than having to add and subtract the measurements of the semi-circle, notice that the semicircle to the left of ad is actually identical in area to the blank semicircle-shaped space to the left of bc. so if we transferred the red semicircle into the blank space, we would end up with a square of side length 24 cm. the area of a square is s^2 = 24^2 = 676 cm^2.

u also answered this so i think u would know but i am here to

put in or use mine