Which of the following is true regarding the solution to the logarithmic equation below?

Answer with explanation:

The given Logarithmic equality is which can be solved as follows:

Used following properties of Log

but, if you substitute x= -6,in the given equation, that is

LHS≠RHS

So, x=6,is only solution of given logarithmic equality

∵

LHS=RHS

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)