Which transformation shows that the two given circles are similar? circle a -- center(2, 0), radius 8 circle a' -- center(-1, 5), radius 3 a)(x, y) → (x - 3, y + 5); scale factor 3/8 b)(x, y) → (x - 3, y + 5); scale factor 8/3 c)(x, y) → (x + 3, y - 5); scale factor 3/8 d)(x, y) → (x + 3, y - 5); scale factor 8/3

if the eqn of the parabola is f(x) = (x-4)(x+2), we need to mult. this out to find the coordinates of the vertex.

then f(x) = x^2 + 2x - 4x - 8, and f(x) = x^2 - 2x - 8.

one way in which you can find the vertex is to calculate x = -b / (2a).   here, that comes to

        )

x = = 1.   f(1) = 1^2 - 2(1) - 8 = - 9.   vertex is at (1, -9).

        2(1) 

find another point on the curve:   let x=0, for which y=-8.   then (0, -8) is on the curve.   plot the vertex and this point and draw a smooth parabola thru both.

hope this

answer: 1) twenty-seven times y

              2) twenty-seven multiplied by y