What is the area of a parallelogram whose vertices are a(−12, 2) , b(6, 2) , c(−2, −3) , and d(−20, −3) ? enter your answer in the box. units²

Let

using a graphing tool

see the attached figure to better understand the problem

we know that

Parallelogram is a quadrilateral with opposite sides parallel and equal in length

so

The area of a parallelogram is equal to

where

B is the base

h is the height

the base B is equal to the distance AB

the height h is equal to the distance AE

Step 1

Find the distance AB

the formula to calculate the distance between two points is equal to

substitute the values

Step 2

Find the distance AE

the formula to calculate the distance between two points is equal to

substitute the values

Step 3

Find the area of the parallelogram

The area of a parallelogram is equal to

substitute the values

therefore

the answer is

the area of the parallelogram is

answer: 42

use a calculator to find that 845/73 = 11.575

the whole part of the answer is 11. multiply this by 73 to get 11*73 = 803.

subtract that result from 845 to get 845 - 803 = 42

hope this is what you were asking for!

step-by-step explanation: