How do you find the y-intercept and the slope for number 11

The first step is to find the slope. Use the slope formula

m = (y2-y1)/(x2-x1)

The two points are (x1,y1) = (-1,5) and (x2,y2) = (2,-1)

So,
x1 = -1
y1 = 5
and
x2 = 2
y2 = -1
will be plugged into the slope formula to get...
m = (y2-y1)/(x2-x1)
m = (-1-5)/(2-(-1))
m = (-1-5)/(2+1)
m = (-6)/(3)
m = -2

The slope is -2

Use m = -2 and one of the points to find the y intercept b. I'll use the point (x,y) = (-1,5) ---> x = -1, y = 5

y = mx+b ... slope intercept form
5 = -2*(-1)+b
5 = 2+b
5-2 = 2+b-2
3 = b
b = 3

The y intercept is 3



m = -2 is the slope
b = 3 is the y intercept

Therefore y = mx+b turns into y = -2x+3 as the equation that goes through the two points