Three friends were born in consecutive years. the some of their birth years is 5982.find the year in which each person was born

The birth years of first person is 1993.

The birth years of second person is 1994.

The birth years of third person is 1995.

Step-by-step explanation:

Three friends were born in consecutive years

Let the birth years of first person be  x,

Let the birth years of second person be (x+1)

Let the birth years of third person be(x+2)

The sum of their birth years is 5982.

Solving the given equation for x:

The birth years of first person = x =  1993

The birth years of second person = (x+1) = 1993+ 1 = 1994

The birth years of third person = (x+2) = 1993+2 = 1995

36

step-by-step explanation:

the simplified form is

step-by-step explanation:

we want to simplify the expression,

let us change the middle bar to a normal division sign to obtain,

we multiply the first fraction by the reciprocal of the second fraction to obtain,

we factor to obtain,

we cancel the common factors to get,

we simplify to get,

the correct answer is b