The perimeter of square a is 24 linear units. the area of square b is 4 times the area of square a. what is the area of square b? what is the perimeter of square b? show your work

area of Square B: 144 quadratic units

perimeter of Square B: 48 linear units

Step-by-step explanation:

The perimeter of a square is  

perimeter = 4*L

where L is the length of each square side. For square A:

24 = 4*L

L = 24/4

L = 6 linear units

The area of a square is  

area = L^2

For square A:

area = 6^2 = 36 quadratic units

The area of Square B is 4 times the area of Square A. So

area of Square B = 4*area of Square A

area of Square B = 4*36

area of Square B = 144 quadratic units

And the length of the sides of the square B can be computed as

area = L^2

L = sqrt(area)

L = sqrt(144)

L = 12 linear units

Therefore, the perimeter of square B is

perimeter = 4*L

perimeter = 4*12

perimeter = 48 linear units

the answer will be b x² +x-1

step-by-step explanation:

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)