What is the equation of a line that passes through the point (9, −3) and is parallel to the line whose equation is 2x−3y=6 ? enter your answer in the box

The equation of the line, in slope-intercept form, that is parallel to 2x - 3y = 6 and passes through (9, -3) is:

Given:

Points the line passes through, (9, -3)

The equation of the line it is parallel to: 2x - 3y = 6

Note:

First, rewrite 2x - 3y = 6 in slope-intercept form to determine its slope.

Thus, the slope of the line that passes through (9, -3) is also 2/3.

Write the equation of the line in point-slope form:

Substitute m = 2/3, and (a, b) = (9, -3) into y - b = m(x - a)

Therefore, the equation of the line, in slope-intercept form, that is parallel to 2x - 3y = 6 and passes through (9, -3) is:

Learn more here:

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here you hope this .

step-by-step explanation:

hypotenuse = √(15² + 8²)

=  √(225 +64)

=  √(289) = 17

sin(x) = cos(y) = 8/17

they are identical so long as you are doing the sine of one angle and the cosine of the only other angle that isn't the right angle.

-2

7 - 9 = -2

reversed:

-2 + 9 = 7