Aball is thrown vertically upward from the top of a 200 foot tower, with an initial velocity of 5 ft/sec. its position function is s(t) = –16t2 + 5t + 200. what is its velocity in ft/sec when t = 3 seconds?

The velocity would be - 91 ft/sec.

Step-by-step explanation:

Given,

The function that shows the position of the ball after t seconds,

Since, velocity is the changes in position with respect to time,

That is, if v(t) is the velocity of the ball after t second,

Hence, the velocity after 3 seconds is,