The angle bisector of ∠DAB is ray _

Solve the following: 12(x^2–x–1)+13(x^2–x–1)=25(x^2–x–1) 364x–64x=300x

Which statement is true about the local minimum of the graphed function? over the interval[-4,-2], the local minimum is 0. over the interval [-2,-1] , the local minimum is 25. over the interval [-1,4], the local minimum is 0. over the interval [4,7], the local minimum is -7

The graph of f(x), shown below, has the same shape as the graph of g(x)=x^2,but is shifted up 2 unit. what is the new equation?