Afisherman yanks a fish vertically out of the water with an acceleration of 2.5! using very light fishing line that has a breaking strength of 22 n. the fisherman unfortunately loses the fish as the line snaps. what can you say about the mass of the fish?

Two forces act on the fish, and these are:

1) Its weight mg, downwards and 

2) pressure in the string, T, upwards which is 22 N when the string breaks. 
In the result of these two forces, the fish had an acceleration of 2.5 m/s^2 in the upward way. 

So, T - mg = m*2.5

=> m = T / (2.5 + g)

=> m > 22 / (2.5 + 9.8) ( when the string snaps ) 

=> m > 1.79 kg. 

As a result, the mass of the fish is more than 1.79 kg as the line has been broken.

anser is a

step-by-step explanation:

negitive slope

step-by-step explanation:

we are given

since, we have to isolate x on anyone side

so, we can move all x terms on one side

subtract both sides by 2x

add both sides by 9

divide both sides by 4

we get