3333% of college students say they use credit cards because of the rewards program. you randomly select 10 college students and ask each to name the reason he or she uses credit cards. find the probability that the number of college students who say they use credit cards because of the rewards program is (a) exactly two, (b) more than two, and (c) between two and five inclusive. if convenient, use technology to find the probabilities.

a. at r = 2

P = [10! / (10 – 2)! 2!] * 0.33^2 * 0.67^(10 – 2)

P = 0.1989 ~ 0.20               (answer)

b. We deduct the values of P when r = 0, r = 1, r = 2 from 1 to get all values when r > 2

at r = 0

P = [10! / (10 – 0)! 0!] * 0.33^0 * 0.67^(10 – 0)

P = 0.0182

at r = 1

P = [10! / (10 – 1)! 1!] * 0.33^1 * 0.67^(10 – 1)

P = 0.0898

so for r > 2, the probability is:

P = 1 – (0.1989 + 0.0182 + 0.0898)

P = 0.6931            (answer)

c. at r = 3

P = [10! / (10 – 3)! 3!] * 0.33^3 * 0.67^(10 – 3)

P = 0.2614

at r = 4

P = [10! / (10 – 4)! 4!] * 0.33^4 * 0.67^(10 – 4)

P = 0.2253

at r = 5

P = [10! / (10 – 5)! 5!] * 0.33^5 * 0.67^(10 – 5)

P = 0.1332

So when r is between 2 and 5 inclusive, the probability is:

P = 0.1989+ 0.2614 + 0.2253 + 0.1332

P = 0.8188            (answer)

an

y = 6x -3y -12

y +3y +12 = 6x

=> . x = { 2y / 3 +2 } this is equation of line in terms of x

=> . if line meets the x-axis the co-ordinates of meeting point would be ( x , 0 )

=> . x = 2 ( 0 ) / 3 + 2

=> . x = 2

so, the point is ( 2 , 0 )

step-by-step explanation:

part a. the differences are decreasing, so we know the sequence is not arithmetic. the ratios are constant (=3/4), so we know the sequence is geometric.

part b. from part a, we know the common ratio is 3/4, so each term is 3/4 of the one before. the initial term is the number of gallons at h=1.

g[h] = (3/4)·g[h-1]

g[1] = 384 . . . . initial value required for a recursive definition

part c. the general formula for a geometric sequence is

a[n] = a[1]·r^(n-1)

we have a[1] = 384, r = 3/4, and the term number given by h. the formula that follows is

g[h] = 384·(3/4)^(h-1)

part d. filling in the value and doing the arithmetic, we have

g[12] = 384·(3/4)^11 ≈ 384·0.042235136 ≈ 16.2183 . . gallons

part e. each gallon is 4 quarts, so

16.2183 gal × 4 qt/gal = 64.8732 qt