One inlet pipe can fill an empty pool in 4 hours, and a drain can empty the pool in 8 hours. how long will it take the pipe to fill the pool if the drain is left open?

Given that one inlet pipe can fill an empty pool in 4 hours. The outlet pipe can empty the pool in 8 hours. We know that rate x time = work done.

Rate = work done / time

Rate of inlet pipe = ¼ hours.

Rate of outlet pipe = 1/8 hours

Here 1 represent the work completed.

Let x be the time taken to fill the pool by the inlet pipe if the drain is left.

Work done by inlet pipe – work done by outlet pipe = 1 work completed.

x/4 – x/8 = 1.

To solve the rational equation, first we clear the fractions by multiplying it with LCD (4,8)=8 to each item.

8(x/4) – 8(x/8) = 8(1)

2x – x = 8

X = 8

Time taken for the pipe to fill the pool if the drain is left open = 8 hours

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

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