Larry lazy purchased a one year membership at a local fitness center at the beginning of the year. it cost him $150. he goes twice a week for the first three months (13 weeks) of the year, but then goes only once a month for the rest of the year. how much does each visit to the center cost? if he continued going twice a week all year, how much would each visit cost?

A. $4.29

B. $1.44

Step-by-step explanation:

A. We have been given that Larry goes to gym twice a week for 13 weeks. Let us multiply 13 by 2 to find the number of times Larry visited the gym for first 3 months.

Since there are 12 months in a year, then Larry has gone to gym only 9 times for rest of month as 12-3=9.

Now let us add 26 and 9 to get the total number of Larry's visits to gym.

Now let us divide total cost (150) by total number of visits (35) to get the each visit's cost.

Therefore, each visit to the center costs $4.29 to Larry.

B. If Larry continued going twice a week all year, then total number of Larry's visits to center will be 52 times 2.

Now let us divide total cost (150) by total visits (104) to find the cost of each visit.

Therefore, If Larry continued going twice a week all year, it would cost  him $1.44 for each visit.

60.9774

step-by-step explanation:

because when you add 47.6 plus 7.32 equals 54.92

and when you add .0574 + 6= 6.0574

and when you add 54.92 and 6.0574 you get the answer of 60.9774.

plzz mark brainlest last one got deleted. cause i didn't explain it but i did but i understand what the mod meant

hello from mrbilldoesmath!

answer:

(7 x + 6 y) (49 x^2 - 42 x y + 36 y^2)

discussion:

the trick is to recognize that 343 = 7^3 and 216 = 6^3 and, in general,

a^3 + b^3 =   (a + b) (a^2 - a b + b^2).

in our case

343x^3+216y^3   =   (7x)^3 + (6y)^3

so take a = 7x and b = 6y in the above equation to get the answer.

you,

mrb