Mathematics

Mathematics, 03.10.2019 03:30, Dianar8407

Write an equation of a line parallel to y=2/3x-1 that contains the point (6,-2)

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Mathematics, 03.07.2019 23:40, taylorwhitfield6

Constructing parallel lines use the slope of the given line to construct a parallel line through point p. click or tap the graph to plot another point on the parallel line. what is the slope of the original line? what is the equation of the line that is parallel to the given line and passes through the given point? the correct graph of the parallel line is shown demo ) intro done what’s the

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Mathematics, 21.07.2019 10:00, raizagisselle1273

12. the table shows the height of a plant as it grows. which equation in point-slope form gives the plant's height at any time (1 point) time (months) | plant height (cm) 2 | 16 4 | 32 6 | 48 8 | 64 (a). y - 16 = 8(x - 2) (b). y - 16 = 8x - 2 (c). y + 16 = 8(x + 2) (d). the relationship is nonlinear 14. write y = (-5/8)x + 3 in standard form using integers (1 point) (a). 5x + 8y = -24 (b). 5x + 8y = 24 (c). 5x - 8y = 24 (d). -5x + 8y = 24 15. write an equation for the line that is parallel to the given line and passes through the given point (1 point) y = 3x + 7; (2, 10) (a). y = 3x + 11 (b). y = 3x + 4 (c). y = -3x + 4 (d). y = (-1/3)x + 4 16. tell whether the lines for each pair of equations are parallel, perpendicular, or neither (1 point) y = -2x + 4 -5x + 10y = 5 (a). parallel (b). perpendicular (c). neither 17. tell whether the lines for each pair of equations are parallel, perpendicular, or neither (1 point) y = -1/4x + 10 -2x + 8y = 6 (a). parallel (b). perpendicular (c). neither 18. write the equation of a line that is perpendicular to the given line and that passes through the given point (1 point) y - 4 = 5/2 (x + 3); (-7, 8) (a). y - 8 = -2/5 (x - 7) (b). y - 8 = 2/5 (x - 7) (c). y - 8 = -2/5 (x + 7) (d). y - 8 = 2/5 (x + 7)

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Mathematics, 28.08.2019 16:30, billy12008

Ineed with a few questions . write the equation of the line that is parallel to the line whose equation is y = -4 and that passes through the point (1, 5). a. y=-5 b. y=-4 c.y=1 d. y=5 a line contains the point (–3, 4). if the slope of the line is -2/3, write the equation of the line using slope intercept form. a. y = -2/3x 2 b. y = -2/3x 4 c. y = 3/2x 2 d. y = -2/3x - 3 write the equation of the perpendicular bisector of rs. point r is located at (–1, 3), and point s is located at (3, 1). a. y = -1/2x 2 b. y = -1/2x 3 c. y = 2x - 5 d. y = 2x

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Mathematics, 04.10.2019 22:20, esdancer3494

3. write the slope-intercept form of the equation of the line described. a. point= (1,-1), parallel to y=-6x+1 b. point= (4,5), parallel to y=1/2x+3 4. write the standard from of the equation of the line through the given point with the given slope. a. point=(-4,4), slope= -7/4 b. point=(1,2), slope= 6 5. write the equation of the line. a. point= (-3,3), parallel to y=0 b. point= (5,-2), perpendicular to x=0

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Write an equation of a line parallel to y=2/3x-1 that contains the point (6,-2)...

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