How does the graph of g(x)=⌈x⌉+7 differ from the graph of f(x)=⌈x⌉? -the graph of g(x)=⌈x⌉+7 is the graph of f(x)=⌈x⌉ shifted down 7 units. -the graph of g(x)=⌈x⌉+7 is the graph of f(x)=⌈x⌉ shifted left 7 units. -the graph of g(x)=⌈x⌉+7 is the graph of f(x)=⌈x⌉ shifted up 7 units. -the graph of g(x)=⌈x⌉+7 is the graph of f(x)=⌈x⌉ shifted right 7 units.

C is the answer

Step-by-step explanation:

I took the test.

(n^3 - n)

= n(n-1)(n+1)

since it is divisible by 3 and 2 ,because it is a multiple 3 consecutive number

if, n-1 is odd then n+1 is also odd, then it is a multiple of 9

but if, n-1 is even then n+1 is also even, then it is a multiple of 4

so, largest multiple = max(9*2, 4*3) = max(18, 12) = 18

given that triangle abc is transformed two times to get triangle

a"b"c"

first abc is transformed in to a'b'c' as follows:

the coordinates of a are (1,-1) and transformed into a'(-1,1)

similarly b (4,-2) became b'(-4,2) and

c(7,-2) became c'(-7,2)

i.e. (x,y) becomes (-x,-y)

this is nothing but reflection about a point here origin.

thus first transformation is reflection on the origin.

next is exactly shifting 3 units down

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