Jodi is cutting out pieces of paper that measures 8 1/2 inches by 11 inches from a larger sheet of paper that has an area of 1000 square inches. what is the greatest possible number of pieces of paper that jodi can cut out of the larger sheet?

The sizes of the pieces of paper are all the same and fixed.  Most likely you'll get the max number of pieces by cutting out pieces with their edges parallel:
top of one parallel to and immediately below (no offset to the left or right) the previous piece. 

We know that the total area of the "mother" piece of paper is 1000 sq in and that the formula for area here would be A = x y, where x is the width of the "mother" piece and y is the height of the "mother piece."

Let's first look at the height, y, of the "mother" piece.  Assume that we're cutting 8.5 by 11 pieces with their 11" sides extending vertically, and their 8.5" sides horiz.

We want to maximize the area taken up by the pieces cut from the "mother" piece.  This area is    x * y = x * (x/8.5) times (y/11).  We use the fact that xy=1000 and solve it for y:  y = 1000/x.

Then x*(x/8.5)(1000/x) is to be maximized.

 x^2    1000
* is to be maximized.  Unfortunately:  That comes to 1000x/8.5, which is not very helpful.

Let's try a different approach.  Let y be the height of the "mother" piece and x the width.  Then, as before, xy = 1000.

Let n be the number of pieces of paper 8.5 by 11.  Then y=11n and x=8.5n.

Let's let x=1000/y.  Then    y=11n and x = 1000/y, or 1000/[11n]).  We
want to maximize n, the number of pieces of paper.  Let's see if this "works:"

Maximize A = xy = (11n) * 1000/

Sorry.  I'm not able to move further forward at the moment.  Hope this discussion is of some use to you.

and y≤ -x +4 .

step-by-step explanation:

we are given a graph for system of inequalities.

in order to write the system of inequalities for the given graph, we need to find the inequality for each of the line separately.

let us find the slope of dotted line first.

taking two coordinates on the graph.

let us say (0,0) and (3,1).

let us find the slope of the line now.

slope of the dotted line would be =.

y-intercept of dotted line is y=0 only.

plugging slope m= and b=0 in slope-intercept form y=mx+b, we get

.

the line is shaded up of that dotted line.

therefore, for shading up we would take greater than inequality symbol > .

and because it's a dotted line we would take only > symbol in place of = sign in above equation of line.

therefore, inequality for dotted line would be

.

let us take two points (3,1) and (0,4) on the solid line.

slope of the solid line would be =.

for the solid line we have y-intercept b= 4.

plugging slope m= -1 and b=4 in slope-intercept form y=mx+b, we get

y = -1x + 4.

the line is shaded down of that solid line.

therefore, for shading down we would take less than inequality symbol < .

and because it's a solid line we would take ≤ symbol in place of = sign in above equation of line.

therefore, inequality for solid line would be

y≤ -x +4 .

B. 2 1/2 feet. multiply 2.5 inches by 12 to get thirty inches then divide by 12 to get 2.5 feet