Ma what are the steps for using a compass and straightedge to construct a line through point a that is parallel to line j? a horizontal line j and a point a are drawn. the point a is below the horizontal line j. drag the steps and drop them in order from start to finish. place the point of the compass on point q and open it to width qr . use the straightedge to draw a line k that passes through a and intersects line j. label the point of intersection as point p. use the straightedge to draw ab←→. without changing the width of the compass opening, place the point of the compass on point a and draw an arc that intersects line k. label the intersection as point s. with the compass opening set to width qr , place the point of the compass on point s and draw an arc that intersects the arc that was drawn from point a. label the intersection of the arcs as point b. place the point of the compass on point p and draw an arc that intersects lines j and k. label the intersections as points q and r.

Step 1:  Use the straightedge to draw a line k that passes through A and intersects line j. Label the point of intersection as point P.  This is because you must have a point of intersection with the line before you can move forward.

Step 2:  Place the point of the compass on point P and draw an arc that intersects lines j and k. Label the intersections as points Q and R.  This will give us a compass width to move forward.

Step 3:  Place the point of the compass on point Q and open it to width ​ QR.  

Step 4:   Without changing the width of the compass opening, place the point of the compass on point A and draw an arc that intersects line k. Label the intersection as point S.   This gives us the point to use to construct the second point of our parallel line.

Step 5:  With the compass opening set to width QR , place the point of the compass on point S and draw an arc that intersects the arc that was drawn from point A. Label the intersection of the arcs as point B.   This is the second point of our parallel line.

Step 6:  Use the straightedge to draw AB←→.  

56.6

step-by-step explanation:

the ratio of the perimeters is equal to the scale.

the ratio of the areas is equal to the square of the scale.

34 / 20 = k

a / 19.6 = k²

substituting:

a / 19.6 = (34 / 20)²

a = 19.6 (34 / 20)²

a ≈ 56.6

circumference divided by 3.141592654 then timesthe radius twice

step-by-step explanation:

circumference divided by 3.141592654 then timesthe radius twice