Mathematics, 10.07.2019 23:10, kodyclancy
What is the equation of a line, in point-slope form, that passes through (−2, −6) and has a slope of 13 ? a)y−2=13(x−6) b) y+6=13(x+2) c) y−6=13(x−2) d) y+2=13(x+6)
Answers: 1
![\bf \begin{array}{lllll} &x_1&y_1\\ % (a,b) &({{ -2}}\quad ,&{{ -6}}) \end{array} \\\\\\ % slope = m slope = {{ m}}= \cfrac{rise}{run} \implies 13 \\\\\\ % point-slope intercept \stackrel{\textit{point-slope form}}{y-{{ y_1}}={{ m}}(x-{{ x_1}})}\implies y-(-6)=13[x-(-2)] \\\\\\ y+6=13(x+2)](/tpl/images/0074/9657/55d2f.png)
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What is the equation of a line, in point-slope form, that passes through (−2, −6) and has a slope of...
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