If a sports car is traveling at 95 miles per hour, how long would it take the sports car to overtake a family car traveling at 35 miles per hour that left the same starting point 4.5 hours earlier?

Distance = speed * time
d = st

The sports car travels d distance for t time at speed, s, 95 mph until it overtakes the family
car.
The equation for the sports car is
d = 95t

The family car travels the same distance, d, but since it left 4.5 hours earlier  than the sports car, it travels for t + 4.5 time until it is overtaken. It travels at speed, 35 mph.
The equation for the family car is
d = 35(t + 4.5)

We solve the two equations as a system of equations.

d = 95t
d = 35(t + 4.5)

Since d = d, set the right sides of the equations above equal to each other.

95t = 35(t + 4.5)

95t = 35t + 157.5

60t = 157.5

t = 2.625

The answer is 2.625 hours, or 2 hours, 37 minutes, and 30 seconds.

Check:
In 2.625 hours, the sports car travels: 95 mph * 2.625 h = 249.375 miles
The family car traveled 2.625 hours plus the extra 4.5 hours, or 7.125 hours.
In 7.125 hours, the family car travels 35 mph * 7.125 h = 249.375 miles.
The cars have traveled the same distance 2.625 hours after the sports car left, so our answer is correct.

If your asking how much altogether for 12 performance the answer will be 98,496.