The saginaw bay tides vary between 2 feet and 8 feet. the tide is at its lowest point when time (t) is 0 and completes a full cycle in 16 hours. what is the amplitude, period, and midline of a function that would model this periodic phenomenon? amplitude = 3 feet; period = 16 hours; midline: y = 5 amplitude = 3 feet; period = 8 hours; midline: y = 3 amplitude = 6 feet; period = 16 hours; midline: y = 5 amplitude = 6 feet; period = 8 hours; midline: y = 3

Option A

amplitude = 3 feet; period = 16 hours; midline: y = 5 amplitude = 3 feet;

Step-by-step explanation:

Given that The saginaw bay tides vary between 2 feet and 8 feet.

When we correspond these to sine curve we can say minimum 2 ft max 8 ft middle value being 5 ft

Period = 16 hours (since it completes one full cycle in 16 hours_

Amplitude = maximum - middle value or middle value-minimum

=

Thus the equation would be as

Thus we find that minimum =2, max =8 middle line y=5

Amplitude = 3 ft and period = 16

Hence option A is right.

(x3 + 6x2 + 2x - 6) • (x - 1)

step-by-step explanation:

polynomial long division :

3.2     polynomial long division

dividing :   x4+5x3-4x2-8x+6

                              ("dividend")

by         :     x-1     ("divisor")

dividend     x4   +   5x3   -   4x2   -   8x   +   6

- divisor   * x3     x4   -   x3            

remainder         6x3   -   4x2   -   8x   +   6

- divisor   * 6x2         6x3   -   6x2        

remainder             2x2   -   8x   +   6

- divisor   * 2x1             2x2   -   2x    

remainder               -   6x   +   6

- divisor   * -6x0               -   6x   +   6

remainder                     0

quotient :   x3+6x2+2x-6   remainder:   0

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step-by-step explanation: