Andrew has six fewer coins than casey. bob has four more than twice as many coins as andrew. altogether, they have 466 coins. how many coins does bob have?

"Andrew has six fewer coins than Casey."

A=C-6

"Bob has four more than twice as many coins as Andrew."

B=2A+4

"Altogether, they have 466 coins."

A+B+C=466



How many coins does Bob have?

B=2A+4

Therefore:

B=2(C-6)+4



A+B+C=466,

Therefore:

(C-6)+(2(C-6)+4)+C=466

C-6+(2C-12+4)+C=466

C-6+(2C-8)+C=466

C-6+2C-8+C=466

4C-14=466

4C=480

C=120



If C=120,

B=2(120-6)+4

B=2 x 114 + 4

B= 228 + 4

B=232



A=120-6

A=114



Answers (including Bob's):

Andrew has 114 coins. Casey has 120 coins. Bob has 232 coins.

114 + 120 + 232 = 466