Mathematics, 10.07.2019 12:20, KATE1223

Solve the system of equations algebraically 3x+2y=4 4x+3y=7 7x+4y+7z=5

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answered: joree

First, take the equations 3x+2y=4 and 4x+3y=7 and solve for x. Note, * means to times.

Solving for x
Cancel out y
3x + 2y = 4
4x + 3y = 7

Times equation 1 3x+2y=4 by -3 ad equation 2 by 2
Equation 1
3x + 2y = 4
-3( 3x+2y) = 4 * -3
-9x - 6y = -12

Equation 2:
2(4x+3y) = 7 * 2
8x + 6y = 14

Now we have two new equations and we can cancel out the y. Here are the two new equations:

-9x - 6y = -12
8x + 6y = 14

Lets solve by canceling out the y. -6y + 6y = 0

-9x - 6y = -12
8x + 6y = 14
-----------------------
-1x + 0 = 2
-1x = 2
$\frac{-1x} {-1} = \frac{2}{-1}$
x = -2

We found x so not lets find y. We can find y like we did for x or we can just insert x = -2 into the equation 3x+2y=4 and solve for y. Lets do that now.
3x+2y=4
3*-2 + 2y = 4
-6 + 2y = 4
-6 + 6 + 2y = 4 + 6
2y = 10
$\frac{2y}{2} = \frac{10}{2}$
y = 5

Now that we have found x and y, we can use this new information and insert -2 for x and 5 for y in the equation 7x+4y+7z=5 and solve for z. Lets do that now.
7x + 4y + 7z = 5
7 * -2 + 4 * 5 + 7z = 5
-14 + 20 + 7z = 5
-14 +14 + 20 - 20 + 7z = 5 + 14 - 20
7z = -1
$\frac{7z}{7} = -\frac{1}{7}$
z = $-\frac{1}{7}$

We are done. So our answers are: x = -2 y = 5 and z = $-\frac{1}{7}$

answered: Guest

37/3

step-by-step explanation:

step 1: simplify both sides of the equation.

7x+8(x+

)=3(6x−9)−8

7x+(8)(x)+(8)(

)=(3)(6x)+(3)(−9)+−8(distribute)

7x+8x+2=18x+−27+−8

(7x+8x)+(2)=(18x)+(−27+−8)(combine like terms)

15x+2=18x+−35

15x+2=18x−35

tep 2: subtract 18x from both sides.

15x+2−18x=18x−35−18x

−3x+2=−35

step 3: subtract 2 from both sides.

−3x+2−2=−35−2

−3x=−37

step 4: divide both sides by -3.

−3x

−3

−37

−3

answered: Guest

(1, –1), (16, –4), (36, –6)

step-by-step explanation:

given that the function is

$f(x) =\sqrt{x}$

this can also be written as

$y^{2} =x$

we have to graph this function and check which list of points lie on the graph

see attachment for graph:

we find that the points lying are (1,-1) (16,-4) and (36,-6)

since square root is there we find that x can only be posiitve but y can be since square root both positive and negative.

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Solve the system of equations algebraically 3x+2y=4 4x+3y=7 7x+4y+7z=5...