The data set below shows the number of cars parked in the restaurant parking lot during the lunch hour each day for two weeks: 8 7 14 10 13 27 11 10 14 7 12 9 14 9 which of the following statements is true based on the data set? there is one outlier that indicates an unusually small number of cars were in the parking lot that day. there are two outliers that indicate an unusually small number of cars were in the parking lot those two days. there is one outlier that indicates an unusually large number of cars were in the parking lot that day. there are two outliers that indicate an unusually large number of cars were in the parking lot those two days.

Based on the data set, the true statement is: C. There is one outlier that indicates an unusually large number of cars were in the parking lot that day.

An outlier can be defined as a data value that is either unusually small or large when compared to the overall pattern of the numerical values in a data set.

This ultimately implies that, an outlier lies outside most of the other values in a particular data set, and as such makes them different from the other numerical values.

In this scenario, there is only one outlier in this data set, which is 27 and it simply indicates an unusually large number of cars were in the parking lot that day.

Read more on outlier here: link

The data set for two weeks that shows the number of cars parked in the restaurant parking lot during the lunch hour each day is given as:

8   7   14   10   13   27   11    10   14   7   12    9   14   9

The statements that hold true according to the data is:

d. 24+-0.114

step-by-step explanation:

the question requires us to calculate the approximate 95% confidence interval for the mean number of ounces of ketchup per bottle in the sample given the following statistics;

sample mean = 24

standard deviation, σ = 0.4

sample size , n = 49

the confidence interval for a population mean is calculated using the formula;

sample mean ± z-score*(σ/sqrt(n))

the z-score associated with a 95% confidence interval, from the standard normal tables, is;

1.96

substituting these values into the formula;

24 ± 1.96*(0.4/7)

= 24 ± 0.112

from the alternatives given, choice d is closest to the above expression;

-4, -2, 1, 4

step-by-step explanation:

domain = x values

range = y values