The sum of three numbers is 45 the second of the three numbers is three more than twice the first number, ×. the thurd number is two more than the first number, ×. which equation can be used to solve the first number

Step-by-step explanation:

We know that the 1st equation + 2nd equation + 3rd equation = 45.  Now we just need to identify from the infor given what these equations are, then set them to equal 45.

It has already been determined that the 1st equation is x.

The second equation is "3 more than twice the first".  Twice the first is 2x, and 3 more is +3; therefore, the second equation is: 2x + 3.

The third equation is "2 more than the first".  2 more than is +2, so the third equation is x + 2.

Now we have all 3:

1st:  x

2nd:  2x + 3

3rd:  x + 2

Add them all up and set them equal to 45:

x + 2x + 3 + x + 2 = 45.

You don't have choices listed, so it's either that one above, or simplified down to:

4x + 5 = 45

After that, any simplification done will be solving the equation.

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